2[x+1]-[x]-3[x+2]=0

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Solution for 2[x+1]-[x]-3[x+2]=0 equation:


Simplifying
2[x + 1] + -1[x] + -3[x + 2] = 0

Reorder the terms:
2[1 + x] + -1[x] + -3[x + 2] = 0
[1 * 2 + x * 2] + -1[x] + -3[x + 2] = 0
[2 + 2x] + -1[x] + -3[x + 2] = 0

Reorder the terms:
2 + 2x + -1x + -3[2 + x] = 0
2 + 2x + -1x + [2 * -3 + x * -3] = 0
2 + 2x + -1x + [-6 + -3x] = 0

Reorder the terms:
2 + -6 + 2x + -1x + -3x = 0

Combine like terms: 2 + -6 = -4
-4 + 2x + -1x + -3x = 0

Combine like terms: 2x + -1x = 1x
-4 + 1x + -3x = 0

Combine like terms: 1x + -3x = -2x
-4 + -2x = 0

Solving
-4 + -2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -2x = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -2x = 0 + 4
-2x = 0 + 4

Combine like terms: 0 + 4 = 4
-2x = 4

Divide each side by '-2'.
x = -2

Simplifying
x = -2

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